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feat: power of product of two reflections #13270
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This PR/issue depends on:
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Would you mind copying your appendix to a github issue, and then linking to that issue from here? |
Thanks for the suggestion. I have done it: #13291 |
PR summary 6c62c04c86Import changesDependency changes
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Let$M$ be a module over a commutative ring $R$ . Let $x, y \in M$ and $f, g \in M^*$ with $f(x) = g(y) = 2$ . The corresponding reflections $r_1, r_2 \colon M \to M$ are given by $r_1z = z - f(z) x$ and $r_2 z = z - g(z) y$ . These are linear automorphisms of $M$ .
We prove that for all$z \in M$ and all $m \in \mathbb{Z}$ , we have:
$$(r_1 r_2)^m z = z + S_{\left\lfloor \frac{m-2}{2} \right \rfloor}(t) (S_{\left\lfloor \frac{m-1}{2} \right \rfloor}(t) + S_{\left\lfloor \frac{m-3}{2} \right \rfloor}(t)) (g(x) f(z) y - g(z) y - f(z) x) + S_{\left\lfloor \frac{m-1}{2} \right \rfloor}(t) (S_{\left\lfloor \frac{m}{2} \right \rfloor}(t) + S_{\left\lfloor \frac{m-2}{2} \right \rfloor}(t)) (f(y) g(z) x - f(z) x - g(z) y)$$
$$(r_1 r_2)^m x = (S_{m}(t) + S_{m - 1}(t)) x - S_{m-1} g(x) y$$
$$r_2(r_1 r_2)^m x = (S_{m}(t) + S_{m - 1}(t)) x - S_{m} g(x) y$$ $t = f(y) g(x) - 2$ and $S_n$ refers to a Chebyshev $S$ -polynomial.
where
These formulas may look ridiculous, but they are necessary for constructing reflection representations of a Coxeter group over an arbitrary ring. See #13291 for more details.